List of relationship() Examples

Examples of relationship()

ch.epfl.lbd.database.temporal.LifeSpan.relationship()
client.net.sf.saxon.ce.type.TypeHierarchy.relationship()
Determine the relationship of one item type to another. @param t1 the first item type @param t2 the second item type @return {@link #SAME_TYPE} if the types are the same; {@link #SUBSUMES} if the firsttype subsumes the second (that is, all instances of the second type are also instances of the first); {@link #SUBSUMED_BY} if the second type subsumes the first;{@link #OVERLAPS} if the two types overlap (have a non-empty intersection, but neithersubsumes the other); {@link #DISJOINT} if the two types are disjoint (have an empty intersection)
com.webobjects.directtoweb.D2WContext.relationship()
net.sf.saxon.type.TypeHierarchy.relationship()
Determine the relationship of one item type to another. @param t1 the first item type @param t2 the second item type @return {@link #SAME_TYPE} if the types are the same; {@link #SUBSUMES} if the firsttype subsumes the second (that is, all instances of the second type are also instances of the first); {@link #SUBSUMED_BY} if the second type subsumes the first;{@link #OVERLAPS} if the two types overlap (have a non-empty intersection, but neithersubsumes the other); {@link #DISJOINT} if the two types are disjoint (have an empty intersection)
org.neo4j.graphdb.traversal.TraversalBranch.relationship()
The relationship for this expansion source. It's the relationship which was traversed to get to this expansion source. @return the relationship for this expansion source.
org.pdf4j.saxon.type.TypeHierarchy.relationship()
Determine the relationship of one item type to another. @param t1 the first item type @param t2 the second item type @return {@link #SAME_TYPE} if the types are the same; {@link #SUBSUMES} if the firsttype subsumes the second (that is, all instances of the second type are also instances of the first); {@link #SUBSUMED_BY} if the second type subsumes the first;{@link #OVERLAPS} if the two types overlap (have a non-empty intersection, but neithersubsumes the other); {@link #DISJOINT} if the two types are disjoint (have an empty intersection)

Examples of org.pdf4j.saxon.type.TypeHierarchy.relationship()

        if (e != this) {
            return e;
        }
        if (Cardinality.subsumes(targetCardinality, operand.getCardinality())) {
            final TypeHierarchy th = visitor.getConfiguration().getTypeHierarchy();
            int relation = th.relationship(operand.getItemType(th), targetType);
            if (relation == TypeHierarchy.SAME_TYPE || relation == TypeHierarchy.SUBSUMED_BY) {
                return Literal.makeLiteral(BooleanValue.TRUE);
            } else if (relation == TypeHierarchy.DISJOINT) {
                // if the item types are disjoint, the result might still be true if both sequences are empty
                if (!Cardinality.allowsZero(targetCardinality) || !Cardinality.allowsZero(operand.getCardinality())) {

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Examples of org.pdf4j.saxon.type.TypeHierarchy.relationship()

        }
        if (type1.isAtomicType()) {
            atomize1 = false;
        }


        if (th.relationship(type0, BuiltInAtomicType.BOOLEAN) == TypeHierarchy.DISJOINT) {
            maybeBoolean0 = false;
        }
        if (th.relationship(type1, BuiltInAtomicType.BOOLEAN) == TypeHierarchy.DISJOINT) {
            maybeBoolean1 = false;
        }

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Examples of org.pdf4j.saxon.type.TypeHierarchy.relationship()

        }


        if (th.relationship(type0, BuiltInAtomicType.BOOLEAN) == TypeHierarchy.DISJOINT) {
            maybeBoolean0 = false;
        }
        if (th.relationship(type1, BuiltInAtomicType.BOOLEAN) == TypeHierarchy.DISJOINT) {
            maybeBoolean1 = false;
        }


        if (!maybeBoolean0 && !maybeBoolean1) {
            int n0 = th.relationship(type0, BuiltInAtomicType.NUMERIC);

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Examples of org.pdf4j.saxon.type.TypeHierarchy.relationship()

        if (th.relationship(type1, BuiltInAtomicType.BOOLEAN) == TypeHierarchy.DISJOINT) {
            maybeBoolean1 = false;
        }


        if (!maybeBoolean0 && !maybeBoolean1) {
            int n0 = th.relationship(type0, BuiltInAtomicType.NUMERIC);
            int n1 = th.relationship(type1, BuiltInAtomicType.NUMERIC);
            boolean maybeNumeric0 = (n0 != TypeHierarchy.DISJOINT);
            boolean maybeNumeric1 = (n1 != TypeHierarchy.DISJOINT);
            boolean numeric0 = (n0 == TypeHierarchy.SUBSUMED_BY || n0 == TypeHierarchy.SAME_TYPE);
            boolean numeric1 = (n1 == TypeHierarchy.SUBSUMED_BY || n1 == TypeHierarchy.SAME_TYPE);

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Examples of org.pdf4j.saxon.type.TypeHierarchy.relationship()

            maybeBoolean1 = false;
        }


        if (!maybeBoolean0 && !maybeBoolean1) {
            int n0 = th.relationship(type0, BuiltInAtomicType.NUMERIC);
            int n1 = th.relationship(type1, BuiltInAtomicType.NUMERIC);
            boolean maybeNumeric0 = (n0 != TypeHierarchy.DISJOINT);
            boolean maybeNumeric1 = (n1 != TypeHierarchy.DISJOINT);
            boolean numeric0 = (n0 == TypeHierarchy.SUBSUMED_BY || n0 == TypeHierarchy.SAME_TYPE);
            boolean numeric1 = (n1 == TypeHierarchy.SUBSUMED_BY || n1 == TypeHierarchy.SAME_TYPE);
            // Use the 2.0 path if we don't have to deal with the possibility of boolean values,

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