Examples of java.math.BigInteger.divideAndRemainder()

java.math.BigInteger.divideAndRemainder()
Returns an array of two BigIntegers containing {@code (this / val)}followed by {@code (this % val)}. @param val value by which this BigInteger is to be divided, and theremainder computed. @return an array of two BigIntegers: the quotient {@code (this / val)}is the initial element, and the remainder {@code (this % val)}is the final element. @throws ArithmeticException {@code val==0}

        BigInteger[] quotAndRem;
        
        // while the number is even...
        while (!strippedBI.testBit(0)) {
            // To divide by 10^i
            quotAndRem = strippedBI.divideAndRemainder(TEN_POW[i]);
            // To look the remainder
            if (quotAndRem[1].signum() == 0) {
                // To adjust the scale
                newScale -= i;
                if (i < lastPow) {

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    StringBuffer s = new StringBuffer ();
    BigInteger n = new BigInteger (1, b);
    while ( n.compareTo (BigInteger.ZERO) > 0 )
    {
      BigInteger[] r = n.divideAndRemainder (BigInteger.valueOf (58));
      n = r[0];
      char digit = b58[r[1].intValue ()];
      s.append (digit);
    }
    while ( lz > 0 )

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        }


        StringBuffer s = new StringBuffer();
        BigInteger n = new BigInteger(1, b);
        while (n.compareTo(BigInteger.ZERO) > 0) {
            BigInteger[] r = n.divideAndRemainder(BigInteger.valueOf(58));
            n = r[0];
            char digit = b58[r[1].intValue()];
            s.append(digit);
        }
        while (lz > 0) {

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            // Check if we can strip off any trailing zeros after decimal point
            BigInteger i = value.unscaledValue();
            int limit = value.scale();
            int nshift = 0;
            for (nshift = 0; nshift < limit; nshift++) {
                BigInteger[] quotRem = i.divideAndRemainder(ten);
                if (quotRem[REM].intValue() != 0) break;
                i = quotRem[QUOT];
            }
            if (nshift > 0) {
               value = new BigDecimal(i, limit - nshift);

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            }
            /* mlo/S = maximum acceptable error, divided by 10^k, if the output is less than d. */
            /* mhi/S = maximum acceptable error, divided by 10^k, if the output is greater than d. */


            for(i = 1;;i++) {
                BigInteger[] divResult = b.divideAndRemainder(S);
                b = divResult[1];
                dig = (char)(divResult[0].intValue() + '0');
                /* Do we yet have the shortest decimal string
                 * that will round to d?
                 */

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            }
        }
        else
            for(i = 1;; i++) {
//                (char)(dig = quorem(b,S) + '0');
                BigInteger[] divResult = b.divideAndRemainder(S);
                b = divResult[1];
                dig = (char)(divResult[0].intValue() + '0');
                buf.append(dig);
                if (i >= ilim)
                    break;

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        if (sdv.negative) {
            seconds = seconds.negate();
        }
        BigDecimal microseconds = seconds.multiply(DecimalValue.BIG_DECIMAL_ONE_MILLION);
        BigInteger intMicros = microseconds.toBigInteger();
        BigInteger[] parts = intMicros.divideAndRemainder(BigInteger.valueOf(1000000));
        sdv.seconds = parts[0].longValue();
        sdv.microseconds = parts[1].intValue();
        return sdv;
    }

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        int scale = value.scale();
        if (scale > 0) {
            BigInteger i = value.unscaledValue();
            while (true) {
                BigInteger[] dr = i.divideAndRemainder(BIG_INTEGER_TEN);
                if (dr[1].equals(BigInteger.ZERO)) {
                    i = dr[0];
                    scale--;
                    if (scale==0) {
                        break;

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            }
            /* mlo/S = maximum acceptable error, divided by 10^k, if the output is less than d. */
            /* mhi/S = maximum acceptable error, divided by 10^k, if the output is greater than d. */


            for(i = 1;;i++) {
                BigInteger[] divResult = b.divideAndRemainder(S);
                b = divResult[1];
                dig = (char)(divResult[0].intValue() + '0');
                /* Do we yet have the shortest decimal string
                 * that will round to d?
                 */

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            }
        }
        else
            for(i = 1;; i++) {
//                (char)(dig = quorem(b,S) + '0');
                BigInteger[] divResult = b.divideAndRemainder(S);
                b = divResult[1];
                dig = (char)(divResult[0].intValue() + '0');
                buf.append(dig);
                if (i >= ilim)
                    break;

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