referral.addLdapUrl( ref );
continue;
}
// parse the ref value and normalize the DN
LdapURL ldapUrl = new LdapURL();
try
{
ldapUrl.parse( ref.toCharArray() );
}
catch ( LdapURLEncodingException e )
{
LOG.error( I18n.err( I18n.ERR_165, ref, referralAncestor ) );
}
DN urlDn = new DN( ldapUrl.getDn().getName() );
urlDn.normalize( session.getCoreSession().getDirectoryService().getSchemaManager()
.getNormalizerMapping() );
if ( urlDn.getNormName().equals( referralAncestor.getDn().getNormName() ) )
{
// according to the protocol there is no need for the dn since it is the same as this request
StringBuilder buf = new StringBuilder();
buf.append( ldapUrl.getScheme() );
buf.append( ldapUrl.getHost() );
if ( ldapUrl.getPort() > 0 )
{
buf.append( ":" );
buf.append( ldapUrl.getPort() );
}
referral.addLdapUrl( buf.toString() );
continue;
}
/*
* If we get here then the DN of the referral was not the same as the
* DN of the ref LDAP URL. We must calculate the remaining (difference)
* name past the farthest referral DN which the target name extends.
*/
int diff = reqTargetDn.size() - referralAncestor.getDn().size();
DN extra = new DN();
// TODO - fix this by access unormalized RDN values
// seems we have to do this because get returns normalized rdns
DN reqUnnormalizedDn = new DN( reqTargetDn.getName() );
for ( int jj = 0; jj < diff; jj++ )
{
extra.add( reqUnnormalizedDn.get( referralAncestor.getDn().size() + jj ) );
}
urlDn.addAll( extra );
StringBuilder buf = new StringBuilder();
buf.append( ldapUrl.getScheme() );
buf.append( ldapUrl.getHost() );
if ( ldapUrl.getPort() > 0 )
{
buf.append( ":" );
buf.append( ldapUrl.getPort() );
}
buf.append( "/" );
buf.append( LdapURL.urlEncode( urlDn.getName(), false ) );
referral.addLdapUrl( buf.toString() );